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6 August, 02:51

A right rectangular prism has a langht of 5cm, a with of 4 cm, and a hight of 3 cm. The dimensions of the prism are doubled. What is the surface area of the enlarged prism?

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  1. 6 August, 03:03
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    Given

    Dimentions of the rectangular prism are

    Step-by-step explanation:l=5cm, b=4cm, h=3cm

    If each dimension is doubled then new prism dimensions are

    L=10cm, B=8cm, H=6cm

    Therefore Required surface area

    Total surface area (TSA) = 2 (LB+BH+LH)

    =2[10*8+8*6+10*6]

    =2 (80+48+60)

    =2*188

    =376square cm
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