A right rectangular prism has a langht of 5cm, a with of 4 cm, and a hight of 3 cm. The dimensions of the prism are doubled. What is the surface area of the enlarged prism?

Given

Dimentions of the rectangular prism are

Step-by-step explanation:l=5cm, b=4cm, h=3cm

If each dimension is doubled then new prism dimensions are

L=10cm, B=8cm, H=6cm

Therefore Required surface area

Total surface area (TSA) = 2 (LB+BH+LH)

=2[10*8+8*6+10*6]

=2 (80+48+60)

=2*188

=376square cm