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Zechariah Preston
Mathematics
14 May, 04:24
Prove sin^3z*cos^2z=sin^3z-sin^5z
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Juicy
14 May, 04:51
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Left hand side
sin^3z * (1 - sin^2z) = RHS
let sin z = y
y^3 * (1 - y^2) = RHS
y^3 - y^6 = RHS
sin^3z - sin^6z = RHS
the answer at RHS should be to the power of 6. u better check it next time
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