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30 September, 21:07

Dimitri is solving the equation x^2 - 10x = 21. Which value must be added to both sides of the equation to make the left side a perfect-square trinomial?

a. 0

b. 4

c. 25

d. 100

+2
Answers (1)
  1. 30 September, 21:33
    0
    We are given the expression x 2 - 10x = 21 where a number is to be added in both sides to complete the equation by completing the square. In this case, (-10/2) ^2 is equal to 25. The number that is added in the left side of the equation is equal then to 25.
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