Your class field trip is to a museum that charges $4 for adults and $2 for students. If cost $60 for 27 tickets for your class, the teacher, and chaperones. How many adult tickets were purchased? How many student tickets were purchased?

3 adults and 24 students

Step-by-step explanation:

We can set-up a system of equations to find the number of adults. We know students and adults attended. We will let s be the number of students and a be the number of adults. Since 27 tickets were purchased, then s+a=27.

We also know they were purchased for $60 and adult tickets cost $4 and student tickets cost $2. We can write 2s+4a=60.

We will solve by substituting one equation into the other. We start by solving the first equation for c. s+a=27 becomes s=27-a.

Now we substitute s=27-a into 2s+4a=60. Simplify and isolate the variable a.

2s+4a=60

2 (27-a) + 4a=60

54-2a+4a=60

54+2a=60

54-54+2a=60-54

2a=6

a=3

This means that 3 adults attended and 24 students attended since 3+24=27.