Determine the solution set of (x - 4) ^2 = 12.

{4 + 2√3, 4 - 2√3}

{4 - 2√3, 4 - 2√3}

{2√3 + 4, 2√3 - 4}

Question

Jazlene Hopkins

Mathematics

20 March, 07:38

Determine the solution set of (x - 4) ^2 = 12.

{4 + 2√3, 4 - 2√3}

{4 - 2√3, 4 - 2√3}

{2√3 + 4, 2√3 - 4}

+2

Answers (2)

Know the Answer?

Gael Schultz · Answer 1

The Answer is A={4 + 2√3, 4 - 2√3}

Liam Dickerson · Answer 2

Take the derivative with respect to x of both sides. You should obtain x-4 = (plus or minus sqrt (12).

Case 1: if x-4=sqrt 12, then x-4=sqrt (4) sqrt (3) = 2sqrt (3). Then x=4+sqrt (3).

Case 2: (you do this)

Determine the solution set of (x - 4) ^2 = 12.{4 + 2√3, 4 - 2√3}{4 - 2√3, 4 - 2√3}{2√3 + 4, 2√3 - 4}

Determine the solution set of (x - 4) ^2 = 12.

{4 + 2√3, 4 - 2√3}

{4 - 2√3, 4 - 2√3}

{2√3 + 4, 2√3 - 4}