What is the Vertex y=2x^2+6

Compare this function to y=ax^2 + bx + c. You can readily see that a=2, b=0 and c=6.

The x-coord. of the vertex is at x = - b / (2a). Subbing the given values for a and b, we get

x = - (0) / (2 (2) = 0. At x = 0, y = 6, so the vertex of this parabola is (0,6). It opens upward.