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7 December, 01:57

Sally found that a solution of x = 2 was extraneous for her function. What would be a possible denominator in Sally's function?

A 4x + 8

B 2x + 12

C x2 - 4

D x2 - 16

+4
Answers (1)
  1. 7 December, 02:21
    0
    x² - 4 would be the denominator in Sally's function ⇒ answer (C)

    Step-by-step explanation:

    * In any rational function the domain of it (values of x) is all the

    real numbers except the numbers which make the

    denominator = 0

    * Ex: In x - 3/x - 2

    ∵ The denominator = x - 2

    ∵ The value of x which make the denominator = 0 is 2

    ∴ The domain is all real number except 2

    * So If you want to know the denominator search for the

    values which make the denominator equal to zero.

    * In the problem sally found that a solution of x = 2 was

    extraneous for the function

    - That means the function not defined at x = 2

    ∵ x = 2⇒ subtract 2 from both sides

    ∴ x - 2 = 0

    * Now look to the answer and find which one when you

    equate it by 0 give you the answer x = 2

    A) ∵ 4x + 8 = 0 ⇒ subtract 8 from both sides

    ∴ 4x = - 8 ⇒ : 4

    ∴ x = - 2 ⇒ not the answer

    B) ∵ 2x + 12 = 0 ⇒ subtract 12 from both sides

    ∴ 2x = - 12 ⇒ : 2

    ∴ x = - 6 ⇒ not the answer

    C) ∵ x² - 4 = 0 ⇒ add 4 to the both sides

    ∴ x² = 4 ⇒ take √ to both sides

    ∴ x = ± 2 ⇒ the answer

    * That means x = 2 or x = - 2

    * x² - 4 would be the denominator in Sally's function
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