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28 November, 11:58

Using the numbers 3, 2, and 4, which of these problems would have a solution of 4?

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  1. 28 November, 12:06
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    Pemdas

    ok if we look at the first one

    exponents first

    2^3=8

    2^3=8

    we have

    4*8/8

    4*8=32

    32/8=4

    das is answer

    the first one is the answer
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