X^2 + (y-k) ^2=21 what is the value of k

Question

Matias Sawyer

Mathematics

19 March, 07:11

X^2 + (y-k) ^2=21 what is the value of k

+1

Answers (1)

Know the Answer?

Karen Liu · Answer 1

Solve for k:

X^2 + (y - k) ^2 = 21

Subtract X^2 from both sides:

(y - k) ^2 = 21 - X^2

Take the square root of both sides:

y - k = sqrt (21 - X^2) or y - k = - sqrt (21 - X^2)

Subtract y from both sides:

-k = sqrt (21 - X^2) - y or y - k = - sqrt (21 - X^2)

Multiply both sides by - 1:

k = y - sqrt (21 - X^2) or y - k = - sqrt (21 - X^2)

Subtract y from both sides:

k = y - sqrt (21 - X^2) or - k = - sqrt (21 - X^2) - y

Multiply both sides by - 1:

Answer: k = y - sqrt (21 - X^2) or k = sqrt (21 - X^2) + y