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11 May, 04:32

Given that the prime factorisation of 198 is 2x (3*3) x11. State the minimum integer value of

n such that square root of 198n is a natural number.

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  1. 11 May, 04:33
    0
    22

    Step-by-step explanation:

    198 = 2*3²*11

    For 198n to be a perfect square, each prime factor must have an even exponent. So the smallest 198n would be:

    198n = 2²*3²*11²

    198n = 4356

    n = 22
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