What is the center of a circle given by the equation (x-3) 2 + (y-9) 2=16

Question

Steve Branch

Mathematics

3 December, 02:38

What is the center of a circle given by the equation (x-3) 2 + (y-9) 2=16

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Answers (1)

Know the Answer?

Armando Landry · Answer 1

The answer is : y = - 1x + 28

how I did it

(x-3) 2 + (y-9) 2=16

1x - 3 times 2 + 1y - 9 times 2 = 16

1x - 6 + 1y - 18 = 16

+6 + 6

1x + 1y - 12 = 16

+12 + 12

1x + 1y = 28

-1x - 1x

1y = - 1x + 28

/1 / 1 / 1

y = - 1x + 28 or y = - x + 28