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28 September, 18:38

How many mL of water do you have to add to 200 mL a 6M solution of K2SO4 to change its concentration to 2.9M

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  1. 28 September, 18:59
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    213.79mL

    Step-by-step explanation:

    C1 (initial concentration) = 6M

    V1 (initial volume) = 200mL

    C1 (final concentration) = 2.9M

    V2 (final volume) = ?

    Using the dilution formula C1V1 = C2V2, the final volume can be obtain as follow:

    C1V1 = C2V2

    6 x 200 = 2.9 x V2

    Divide both side by 2.9

    V2 = (6 x 200) / 2.9

    V2 = 413.79mL

    To obtain the volume added, we'll take the difference between the final volume and the initial volume. This is illustrated below:

    Volume added = V2 - V1

    Volume added = 413.79 - 200

    Volume added = 213.79mL

    Therefore, the volume of water added to the solution is 213.79mL
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