How many mL of water do you have to add to 200 mL a 6M solution of K2SO4 to change its concentration to 2.9M

213.79mL

Step-by-step explanation:

C1 (initial concentration) = 6M

V1 (initial volume) = 200mL

C1 (final concentration) = 2.9M

V2 (final volume) = ?

Using the dilution formula C1V1 = C2V2, the final volume can be obtain as follow:

C1V1 = C2V2

6 x 200 = 2.9 x V2

Divide both side by 2.9

V2 = (6 x 200) / 2.9

V2 = 413.79mL

To obtain the volume added, we'll take the difference between the final volume and the initial volume. This is illustrated below:

Volume added = V2 - V1

Volume added = 413.79 - 200

Volume added = 213.79mL

Therefore, the volume of water added to the solution is 213.79mL