Which quadratic function has one real solution?
0 = 2 (x + 7) (x - 5)
0 = (x - 3) (x - 3) The quadratic function f (x) = - x2 - 6x - 8 is graphed.
What are the solutions of the quadratic equation 0 = - x2 - 6x - 8?
2 and - 4
-2 and 4
-2 and - 4
2 and 4
0 = 2.4 (x - 2) (x + 2)
0 = (x - 2) (x - 1)
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