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1 September, 19:32

How many tissues should the kimberly clark corporation package of kleenex contain? researchers determined that 60 tissues is the mean number of tissues used during a cold. suppose a random sample of 100 kleenex users yielded a mean of 52 tissues used during a cold with a standard deviation of 22. suppose the alternative you wanted to test was h1: µ < 60. if the critical value in this situation at an α =.05 is - 1.6604, when should we reject the null?

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  1. 1 September, 19:40
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    Step-by-step explanation:

    For the null hypothesis,

    µ = 60

    For the alternative hypothesis,

    h1: µ < 60

    This is a left tailed test

    Since the population standard deviation is not given, the distribution is a student's t.

    Since n = 100,

    Degrees of freedom, df = n - 1 = 100 - 1 = 99

    t = (x - µ) / (s/√n)

    Where

    x = sample mean = 52

    µ = population mean = 60

    s = samples standard deviation = 22

    t = (52 - 60) / (22/√100) = - 3.64

    We would determine the p value using the t test calculator. It becomes

    p = 0.00023

    We would reject the null hypothesis if α = 0.05 > 0.00023
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