The length of marshall's poster is 2 times its width. if the perimeter is 72 inches, what is the area of the poster

In this problem the most important information that is given is that the length of Marshall's poster is 2 times the width of the poster. Also the perimeter of the rectangle is given as 72 inches.

Let us assume that the length of the rectangle = x

Then the width of the rectangle = 2x

Now

Perimeter of a rectangle = 2 (length + width)

72 = 2 (x + 2x)

72 = 2 * 3x

72 = 6x

x = 72/6

= 12

So

Length of the rectangle = 12 inches

Width of the rectangle = 2x

= 2 * 12 inches

= 24 inches

Then

Area of the rectangle = Length * Width

= 12 * 24

= 288 inches ^2

So the area of the given rectangle is 288 inches^2