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7 October, 11:01

Rewrite with only sin x and cos x.

sin 3x - cos x

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  1. 7 October, 11:22
    0
    sin 3x - cos x = 3 (sin x) (cos x) (cos x) - (sin x) (sin x) (sin x) - cos x

    Step-by-step explanation:

    sin 3x - cos x

    This uses Trig Identities.

    sin 3x = sin (x + x + x) = sin (x+x) * cos x + cos (x + x) sin x

    = 2sinxcosx * cos x + [ (cos x) (cos x) - (sin x) (sin x) ] (sin x)

    sin 3x - cos x = 2sinxcosx * cos x + [ (cos x) (cos x) - (sin x) (sin x) ] (sin x) - cos x

    sin 3x - cos x = 2sinxcosx * cos x + sinx (cos x) (cos x) - (sin x) (sin x) (sin x) - cos x

    sin 3x - cos x = 3 sinx cosx * cos x - (sin x) (sin x) (sin x) - cos x

    sin 3x - cos x = 3 (sin x) (cos x) (cos x) - (sin x) (sin x) (sin x) - cos x
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