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4 August, 03:35

The whole number p is greater than 0 a multiple of 6 and a factor of 180. how many possibilities are there for the value

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  1. 4 August, 04:02
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    Hello,

    p=6*k

    p∈div 180

    180=2²*3²*5.

    We take 2*3 remainder 2^1*3^1*5^1

    Number of possibilities: (1+1) * (1+1) * (1+1) = 8
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