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22 February, 00:46

David opened a coffee shop and sold 60 mochas the first day at $2 per cup. He wants to increase the price per cup to increase his revenue. He found out that for every $0.25 increase, x, in the price per cup, the number of cups he sold decreased by 2 per day. How can David find the equation which represents his daily revenue, in dollars, from mocha sales when the price is increased x times?

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  1. 22 February, 00:57
    0
    Multiply (60 - 2x) and (2 + 0.25x) to create the equation y = - 0.5x2 + 11x + 120

    Step-by-step explanation:

    Here, x represents the times at which the price is increased,

    Since, the original price of one cup = $ 2,

    So, after increasing x times of $ 0.25, the new price of each cup = 2 + 0.25x,

    Also, the original number of mochas = 60,

    Given,

    With increasing the price $ 0.25, x times, the number of cup is decreased by 2 times of x,

    That is, the new number of mochas = 60 - 2x

    Hence, the total revenue would be,

    y = new price of each cup * new number of mochas

    ⇒ y = (2 + 0.25x) (60 - 2x)

    ⇒ y = 120 - 4x + 15x - 0.5x²

    ⇒ y = - 0.5x² + 11x + 120

    He can find find the equation which represents his daily revenue, by Multiplying (60 - 2x) and (2 + 0.25x) to create the equation y = - 0.5x² + 11x + 120
  2. 22 February, 01:07
    0
    Answer: Multiply (60 - 2x) and (2 + 0.25x) to create the equation y = - 0.5x2 + 11x + 120

    We know that David wants to increase the price per cup to increase his revenue. He found out that for every $0.25 grows (increase), x, in the price for each cup.

    In the event of a price increase, 2 cups remain unsold, and doubling the cups is still not sold. Then the numbers are sold (60-2x). Depending on the choice:

    Revenue = (60 - 2x) (2 + 0.25x)

    60·2 + 60·0.25x - 2x·2 - 2x·0.25x

    = - 0.5x² + 11x + 120
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