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9 July, 17:53

What is the remainder when the product of the 5 smallest prime numbers is divided by 42?

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  1. 9 July, 18:02
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    55

    Step-by-step explanation:

    The five smallest prime numbers are 2, 3, 5, 7 and 11.

    2 * 3 * 5 * 7 * 11

    = 2310

    Divide by 42.

    2310/42

    = 55
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