Find algebraically in RxR using substituting method the S. S. of the two equations:

X + y = 4

,

2 x - y = 5

x=3 y=1

Step-by-step explanation:

x+y=4

y=-x+4

plug in the y

2x - (-x+4) = 5

2x+x-4=5

3x=9

x=3

plug in x=3 into first equation to find y

y = - (3) + 4

y=-3+4

y=1

Step-by-step explanation:

x + y = 4 equation 1

2x - y = 5 equation 2

using substitution method,

x = 4 - y equation 3

substitute equation 3 into equation 2

2 (4-y) - y = 5

8 - 2y - y = 5

8 - 3y = 5

-3y = 5 - 8

-3y = - 3

divide through by - 3

-3y/-3 = - 3/-3

y = 1

substitue the value of y into equation 1

x + y = 4

x + 1 = 4

x = 4 - 1

x = 3

Hence, x = 3 and y = 1