Bowl contains 8 red balls, and 7 blue balls, and you draw 4 balls.

In how many ways can the selection be made so that at least one of each color is draw?

16? I'm not too good with probability but my guess is that there are two possible positions for each marble and 4 marbles so 1/2*1/2*1/2*1/2 would be 1/16 meaning 16 possible outcomes but I has to have one of each at least so 14