Bowl contains 8 red balls, and 7 blue balls, and you draw 4 balls.

In how many ways can the selection be made so that at least one of each color is draw?

Question

Romeo Harmon

Mathematics

20 November, 11:28

Bowl contains 8 red balls, and 7 blue balls, and you draw 4 balls.

In how many ways can the selection be made so that at least one of each color is draw?

+5

Answers (1)

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Mcneil · Answer 1

16? I'm not too good with probability but my guess is that there are two possible positions for each marble and 4 marbles so 1/2*1/2*1/2*1/2 would be 1/16 meaning 16 possible outcomes but I has to have one of each at least so 14

Bowl contains 8 red balls, and 7 blue balls, and you draw 4 balls.In how many ways can the selection be made so that at least one of each color is draw?

Bowl contains 8 red balls, and 7 blue balls, and you draw 4 balls.

In how many ways can the selection be made so that at least one of each color is draw?