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1 December, 22:44

What is the value of b so that the equation x^2+bx+5=0 will have x intercepts (-5,0) and (-1,0)

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  1. 1 December, 22:46
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    Plug one intercepts: (-1) ^2 + (-1) b+5=0

    (-5) ^2 + (-5) b+5=0

    simplify: 6-b=0

    30-5b=0

    solve for b: 6=b

    30/5=b
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