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20 August, 11:44

Which function describes the graph below? On a coordinate plane, a curve crosses the y-axis at (0, 7), decreases to negative 1, and then increases again to 7. y = 8 cosine (x) + 3 y = 4 cosine (x) + 3 y = 4 sine (x) + 3 y = 8 sine (x) + 3

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  1. 20 August, 12:07
    0
    Pretty sure its' b (y=4Cos (x) + 3)

    Step-by-step explanation:

    Take the max minus the min, equals 8 then times 1/2 equals 4.

    Since it starts at the max, that is a characteristic of cosine NOT sine.

    P. s I know this is late, but for other people
  2. 20 August, 12:09
    0
    y = 4 cosine (x) + 3

    Step-by-step explanation:

    A curve crosses the y-axis at (0, 7)

    This means that when x = 0, y = 7

    We have that:

    sin (0) = 0, cos (0) = 1.

    Let's see which of the functions respect this condition:

    y = 8 cosine (x) + 3

    y (0) = 8cos (0) + 3 = 8 + 3 = 11. Incorrect.

    y = 4 cosine (x) + 3

    y (0) = 4cos (0) + 3 = 4 + 3 = 7. Correct.

    y = 4 sine (x) + 3

    y (0) = 4sin (0) + 3 = 0 + 3 = 3. Incorrect.

    y = 8 sine (x) + 3

    y (0) = 8sin (0) + 3 = 0 + 3 = 3. Incorrect.

    Decreases to negative 1, and then increases again to 7.

    This means that the amplitude is 7 - (-1) = 8, which means that the term which multiplies the function is 8/2 = 4. From above, we have already seen that the answer is y = 4 cosine (x) + 3.
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