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21 October, 16:06

3x^2 + 64 = 2x^2/2 find the roots of the quadratic equation

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  1. 21 October, 16:34
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    4√2i, - 4√2i.

    Step-by-step explanation:

    3x^2 + 64 = 2x^2/2

    3x^2 + 64 = x^2

    2x^2 + 64 = 0

    2x^2 = - 64

    x^2 = - 32

    x = + / - √-32

    x = + / - √16 * - 2

    x = + / - 4√2 i.
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