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29 January, 23:16

Completely factor 4x^3 - 12x^2 + 2x - 6

A. (4x^2 + 3) (x - 2)

B. (4x^2 + 2) (x - 3)

C. (4x^2 - 2) (x + 3)

D. (4x^2 - 3) (x + 2)

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Answers (1)
  1. 29 January, 23:45
    0
    B. (4x^2 + 2) (x - 3)

    Step-by-step explanation:

    4x^3 - 12x^2 + 2x - 6

    Factor by grouping

    4x^3 - 12x^2 + 2x - 6

    Factor 4x^2 out of the first group and 2 out of the second group

    4x^2 (x-3) + 2 (x-3)

    Now factor out (x-3)

    (x-3) (4x^2 + 2)

    To factor completely we should factor out a 2

    (x-3) 2 (2x^2 + 1)

    2 (x-3) (2x^2+1) but since this is not one of the choices, go with B
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