Find three consecutive odd integers, such that five more than the smallest integer is equal to 25 less than 3 times the largest number. Show work

Let x be the smallest number and y be the largest number.

3y-25-5 = x

x+4=y

3 (4+x) - 25-5 = x

12+3x-25-5 = x

3x-x=-12+25+5

2x/2 = 18/2.

X = 9

x+4=y

(9) + 4=y

13. = y

The second number is 11.