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31 August, 07:27

Two candidates attempts to solve a quadratic equation of form / (x^2 px q=0/) one starts with a wrong value of p and find the roots to be 2 and 6 the other starts with a wrong value of q and finds the roots to be 2, - 9 the correct roots are :

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  1. 31 August, 07:48
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    Hello,

    Nice like problem.

    (x-a) (x-b) = x² - (a+b) x+ab=x²-Sx+P

    1) S=8, P=12 value of P is correct

    2) S=-7, P=-18, Value of S is correct

    x²-7x+12=0

    Δ=7²-4*12=1

    x = (7-1) / 2 = 3

    or x = (7+1) / 2=4

    The correct roots are 3 and 4
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