F (1) = 2x^3 - 3x^2 + 7

Question

Shea Melton

Mathematics

23 January, 13:52

F (1) = 2x^3 - 3x^2 + 7

+3

Answers (2)

Know the Answer?

Nobel · Answer 1

f = 2x^3 - 3x^2 + 7

Alena Maldonado · Answer 2

f (-1) = 2x3-3x2+7.

Step-by-step explanation:

Step 1:

Equation at the end of step 1:

-f - (((2 • (x3)) - 3x2) + 7) = 0

Step 2:

Equation at the end of step 2:

-f - ((2x3 - 3x2) + 7) = 0

Pull out like factors:

-f - 2x3 + 3x2 - 7 =

-1 • (f + 2x3 - 3x2 + 7)

f + 2x3 - 3x2 + 7 is not a perfect cube

-f - 2x3 + 3x2 - 7 = 0