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12 April, 08:24

A person wishes to mix coffee worth $9 per lb with coffee worth $3 per lb

to get 120 lb

of a mixture worth $5 per lb

How many pounds of the $9 and the $3 coffees will be needed?

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Answers (1)
  1. 12 April, 08:44
    0
    To answer the question, let x be the number of pounds of coffee worth $9. Having said that, the number of pounds of coffee worth $3 is 120 - x. The equation relating the items before and after mixing is,

    (x) ($9) + (120 - x) ($3) = (120) ($5)

    The value of x is 40. Therefore, the amount of coffee worth $9 and $3 to be used are 40 and 80 pounds, respectively.
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