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2 April, 05:12

Write the quadratic equation Y equals X squared minus 6X + 7 in vertex form

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Answers (2)
  1. 2 April, 05:25
    0
    y = (x+3) ^ 2 - 2

    ps, the ^ means "to the power of"
  2. 2 April, 05:31
    0
    Y=x^2-6x+7

    vertex form is

    y=a (x-h) ^2+k

    basically complete the squaer

    move 7 over to oth er side

    y-7=x^2-6x

    look at inner to coplete square

    x^2-6x

    make sure n umber in front of x^2 is 1, it is

    now divide the constant in front of the x term by 2 and square it (-6/3=-3, (-3) ^2=9)

    now add that to both sides

    y+9-7=x^2-6x+9

    comlete the squaer

    y+9-7 = (x-3) ^2

    add

    y+2 = (x-3) ^2

    minus 2

    y=1 (x-3) ^2-2

    equation is

    y=1 (x-3) ^2-2
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