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29 April, 11:21

Find two consecutive numbers with a product of 121

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  1. 29 April, 11:43
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    One number: x

    Its consecutive: x + 1

    Product:

    x (x+1) = 121

    x² + x - 121 = 0

    Δ = 1² - 4.1. (-121)

    Δ = 1+484

    Δ = 485

    As square root of 485 is not integer, do not exist two consecutive numbers with product of 121
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