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6 January, 13:19

The length of a rectangle is twice its width. if the area of the rectangle is 50 yds2, find its perimeter

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  1. 6 January, 13:32
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    Hello:

    x : length y : width

    xy = 50 ... (1)

    x = 2y ... (2)

    dubsct in (1):

    (2y) (y) = 50

    y² = 25

    y = 5

    x = 10
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