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Reagan
Mathematics
10 October, 20:40
How to show your work to solve 3r^2-16r-7=5
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Keith Garner
10 October, 21:07
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OK so 3r^2-16r-7=5
Subtract five from both sides
3r^2-16r-7-5=0
Add like terms
3r^2-16r-12=0
Factorise it, this means putting it into brackets
(3r + 2) (r - 6)
Find out what multiplies to make negative twelve but adds to make negative sixteen
However none of the terms do this so we put negatives next to the "r"s
(-3r + 2) (-1r - 6)
The answer is r=6
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