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10 October, 20:40

How to show your work to solve 3r^2-16r-7=5

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  1. 10 October, 21:07
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    OK so 3r^2-16r-7=5

    Subtract five from both sides

    3r^2-16r-7-5=0

    Add like terms

    3r^2-16r-12=0

    Factorise it, this means putting it into brackets

    (3r + 2) (r - 6)

    Find out what multiplies to make negative twelve but adds to make negative sixteen

    However none of the terms do this so we put negatives next to the "r"s

    (-3r + 2) (-1r - 6)

    The answer is r=6
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