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28 January, 07:09

3 + d < 3 - d. Solve

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  1. 28 January, 07:34
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    For the sake of solving, temporarily replace the < sign with an = sign. Solve as you normally would.

    3 + d = 3 - d

    add d to both sides

    3 + 2d = 3

    Subtract 3 from both sides

    2d = 0

    Now replace the = sign with the < sign again.

    2d < 0

    Divide both sides by 2 to get your final answer.

    d < 0

    If you are ever uncertain with an answer to an inequality, the best thing to do is plug in a random number! (In this case, make sure the number is less than 0)

    3 + (-1) < 3 - (-1)

    3 - 1 < 3 + 1

    2 < 4

    (-1) is less than zero, and when plugged into the inequality the values of the left side is less than the value of the right side. This shows that d IS < 0.
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