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24 September, 10:34

Calculate work of a man holding a barbell at chest hight 2 m for 15 seconds?

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  1. 24 September, 10:49
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    Answer: 0J

    The equation for work is W=Fdcos (x), where w=work, f=force, d=displacement, and x=angle the force makes with the displacement vector.

    Since the man is holding a barbell and the object, the barbell, isn't being displaced, d=0, making the work done equal to zero.
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