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Tobias Carrillo
Mathematics
28 February, 18:26
Factor each expression 27-9x+15y
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Brodie Mckenzie
28 February, 18:31
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27 = 3 · 9
9x = 3 · 3x
15y = 3 · 5y
27 - 9x + 15y = 3 (9 - 3x + 5y)
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Abel Gordon
28 February, 18:52
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So to factorise 27-9x+15y you need the HCM (highest common factor) of 27, 9 and 15.
HCM: 3
So you divide each of the numbers by 3 and you get
27 divided by 3 = 9
9 divided by 3 = 3
15 divided by 3 = 5
So you take the HCM (3) and then the numbers divided by it and put it into brackets
3 (9-3x+5y)
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