The paper cup is 9 cm tall and the circular opening has a radius of 2.5 cm.

What is the minimum amount of paper needed to make the paper cup to the nearest whole cm² assuming no overlap in the paper?

181cm^2

Step-by-step explanation:

The minimum amount of paper needed to make the cup to the nearest whole number will be = to the surface area of the cylinder = A=2πrh+2πr2.

Where π = 22/7, r = 2.5cm, h = 9cm

A = 2*22/7*2.5*9+2*22/7*2.5*2.5

A = 141.428+39.285

A = 180.713

A = 181cm^2