Of the people who fished at Clearwater Park today, 45 had a fishing license, and 5 did not. Of the people who fished at Mountain View Park today, 30 had a license, and 30 did not. (No one fished at both parks.) Suppose that one fisher from each park is chosen at random. What is the probability that the fisher chosen from Clearwater had a license and the fisher chosen from Mountain View did not have a license? Do not round your answer.

Question

Alexa Campos

Mathematics

22 July, 12:32

Of the people who fished at Clearwater Park today, 45 had a fishing license, and 5 did not. Of the people who fished at Mountain View Park today, 30 had a license, and 30 did not. (No one fished at both parks.) Suppose that one fisher from each park is chosen at random. What is the probability that the fisher chosen from Clearwater had a license and the fisher chosen from Mountain View did not have a license? Do not round your answer.

+3

Answers (1)

Know the Answer?

Rylee Richmond · Answer 1

The probability that a fisherman from Clearwater had a licence is 45/50, and that the one from Mountain View did not is 30/60.

Step-by-step explanation:

45 in Clearwater had licences, and 5 didn't. That's a total of 50. 30 in Mountain View did, and 30 didn't. That's 60.

45 + 5 = 50 45/50 or 9/10 had licences-Clearwater

30 + 30 = 60 30/60 or 1/2 didn't have licences-Mountain View