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26 January, 15:05

For the graph, what is a reasonable constraint so that the function is at least 200? graph of y equals minus 2 times the square of x plus 30 times x plus 200 - 5 ≤ x ≤ 20 0 ≤ x ≤ 15 x ≥ 0 All real numbers

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  1. 26 January, 15:10
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    The correct constraint is:

    0 ≤ x ≤ 15

    Step-by-step explanation:

    The function given to us in the question is:

    y = - 2x² + 30x + 200

    It is given that the function is at least 200, we can write is as:

    -2x² + 30x + 200 ≥ 200 ⇒ Equation (i)

    To find the constraint, replace ≥ sign with = sign and solve for x:

    -2x² + 30x + 200 = 200

    -2x² + 30x = 0

    x (-2x + 30) = 0

    x = 0, - 2x + 30 = 0

    x = 0, - 2x = - 30

    x = 0, x = - 30/-2

    x = 0, x = 15

    So the end values of constraint are 0 and 15.

    Take any value between 0 and 15 and substitute in equation (i) to see whether it satisfies the equation or not.

    -2x² + 30x + 200 ≥ 200

    Substitute x = 5 in the equation:

    -2 (5) ² + 30 (5) + 200 ≥ 200

    -50 + 120 + 200 ≥ 200

    270 ≥ 200

    As the equation satisfies. it means that the solution lies between 0 and 15, including the end values.

    Hence.

    0 ≤ x ≤ 15
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