Find A, B, C where 5x^2 + Ax - 7 = B (x+2) ^2 + C

where A, B, C are constants

Question

Deangelo Griffin

Mathematics

25 September, 12:19

Find A, B, C where 5x^2 + Ax - 7 = B (x+2) ^2 + C

where A, B, C are constants

+5

Answers (1)

Know the Answer?

Efrain Ashley · Answer 1

Expanding the right side:-

5x^2 + Ax - 7 = Bx^2 + 4Bx + 4B + C

Equating coefficients of x^2:-

B = 5

Equating coefficients of x:-

A = 4B

so

A = 4*5 = 20

Equating constants terms

-7 = 4B + C = 20 + C

C = - 27

A=20, B = 5 and C = - 27

Find A, B, C where 5x^2 + Ax - 7 = B (x+2) ^2 + Cwhere A, B, C are constants

Find A, B, C where 5x^2 + Ax - 7 = B (x+2) ^2 + C

where A, B, C are constants