If 2.40 moles of gas are held at a temperature of 97.0 °C in a container with a volume of 45.0 L, what is the pressure of the gas? A. 93.2 kPa B. 101 kPa C. 148 kPa D. 164 kPa

Ideal Gas Law: PV=nRT

R is the universal gas constant of 8.31.

T is temperature in Kelvins. (add 273 to the Celsius temperature (273 + 97 = 370).

Fill in the letters with the given information:

P (45.0) = (2.40) (8.31) (370)

Simplify the right side:

P (45.0) = 7379.28

Divide both sides by 45.0

P = 7379.28 / 45.0

P = 163.984

Round to 164

Answer is D.