The graph of the function f (x) = ax2 + bx + C

(where a, b, and care real and nonzero) has two

x-intercepts. Explain how to find the other x-

intercept if one x-intercept is at

C + 3,0).

Question

Noemi Kramer

Mathematics

19 November, 05:57

The graph of the function f (x) = ax2 + bx + C

(where a, b, and care real and nonzero) has two

x-intercepts. Explain how to find the other x-

intercept if one x-intercept is at

C + 3,0).

+2

Answers (1)

Know the Answer?

Diamond Stuart · Answer 1

The axis of symmetry is - b/2a

The x-intercept shown is 3 units away from the axis of symmetry.

The other x-intercept also must be 3 units away from the axis of symmetry but on the opposite side.

Subtract 3 from the axis of symmetry.

The other x-intercept is (-b/2a-3,0)

The graph of the function f (x) = ax2 + bx + C(where a, b, and care real and nonzero) has twox-intercepts. Explain how to find the other x-intercept if one x-intercept is atC + 3,0).

The graph of the function f (x) = ax2 + bx + C

(where a, b, and care real and nonzero) has two

x-intercepts. Explain how to find the other x-

intercept if one x-intercept is at

C + 3,0).