Find the zeros of the function. f (x) = 9x^2-12x-5

X=5/3, - 1/3

You can use the quadratic formula or you can do any method that your teacher teaches you (box, etc.)

Answer: 5/3 and - 1/3

Explanation:

1) Set the given function equal to 0: 9x^2 - 12x - 5 = 0

2) make 9x^2 = (3x) ^2 and 12x = 4 (3x)

=> (3x) ^2 - 4 (3x) - 5 = 0

3) Factor the polynomial:

(3x - ) (3x + ) first stept of factoring.

Now find two numbers that sum - 4 and their product of - 5, those are - 5 and + 1: = >

(3x - 5) (3x + 1) = 0

4) Set the two factors equal to 0:

3x - 5 = 0 = > 3x = 5 = > x = 5/3 ↔ one root

3x + 1 = 0 = > 3x = - 1 = > x = - 1/3 ↔ the other root.