There were 75 roasted turkeys at Ally's Eats. Bob's Goods had 4/5 as many roasted turkeys as Ally's Eats. If Ally's Eats had 5/6 as many roasted turkeys as Charlotte's Market what was the average number of roasted turkeys owned by each of the three shops?

Question

Leon Vaughan

Mathematics

13 January, 06:53

There were 75 roasted turkeys at Ally's Eats. Bob's Goods had 4/5 as many roasted turkeys as Ally's Eats. If Ally's Eats had 5/6 as many roasted turkeys as Charlotte's Market what was the average number of roasted turkeys owned by each of the three shops?

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Answers (1)

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Nyasia Keith · Answer 1

Step-by-step explanation:

Roasted turkey in Ally's Eats = 75

Roasted turkey in Bob's goods = 4 / 5 x Ally's Eats

= (4 / 5) x 75

= 60

Roasted turkey in Charlotte's Market = N (let)

Given

5/6 N = 75

N = 6 / 5 x 75

= 90

Roasted turkey in Charlotte's Market = 90.