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Find three consecutive integers such that the largest is 3 less than twice the smallest

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  1. 23 May, 11:04
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    The three consecutive integers are 5,6,7

    Step-by-step explanation:

    Let the three consecutive integers be represented as x, x+1, x+2

    As per the requirement, largest integer is 3 less than twice the smallest.

    => x + 2 = 2x - 3

    => 2x - x = 2+3

    => x = 5

    So the three integers are 5,6,7

    Verification:

    Largest integer = 7

    Smallest integer = 5

    2 * smallest integer - 3 = 2 * 5 - 3 = 7

    Largest integer is also 7.

    So the required condition in the question is satisfied by these three integers.
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