Ask Question
9 October, 04:40

I have a circular necklace with $18$ beads on it. All the beads are different. Making two cuts with a pair of scissors, I can divide the necklace into two strings of beads. If I want each string to have at least $6$ beads, how many different pairs of strings can I make?

+1
Answers (1)
  1. 9 October, 04:50
    0
    Solution:

    There are four general types we can make: (6,12), (7,11), (8,10), (9,9).

    First type: (6,12), there are 18 possible ways to choose those 6, which are going to be cut from the necklace: choose a direction to count the beads, and choose a starting position (between 2 beads). There are exactly 18 starting positions, since there are 18 spaces between the beads. One cut is equivalent for a pair we can make.

    Second type: (7,11), with the same reasoning, there are 18 possible ways to cut the necklace.

    Third type: (8,10), with the same reasoning, there are 18 possible ways to cut the necklace.

    Fourth type: (9,9), The same reasoning cannot be applied again, since half of the cuts would be exactly the same as the other half. So there are 9 possible cuts, exactly one or each axis of symmetry for the necklace.

    The solution will be the sum these values: 18+18+18+9=63
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “I have a circular necklace with $18$ beads on it. All the beads are different. Making two cuts with a pair of scissors, I can divide the ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers