Mrs. Synder must choose two of her homeroom students to be class representatives. The class consists of 13 girls and 9 boys. Approximately what percent chance is there that the first student chosen is a boy and the second student chosen is a girl? (Round to the nearest percent)

Question

Jake Jackson

Mathematics

2 May, 20:56

Mrs. Synder must choose two of her homeroom students to be class representatives. The class consists of 13 girls and 9 boys. Approximately what percent chance is there that the first student chosen is a boy and the second student chosen is a girl? (Round to the nearest percent)

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Answers (1)

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Samantha Terrell · Answer 1

Relative frequency = event*sample space

13 girls + 9 boys = 22 students

9/22 = 4090909091

4090909091*100 = 40. 9 ... % = 41% (rounded)

There is a chance of 41% of the first chosen being a boy.

Since, a boy has already been a boy, we need to remove this number from the sample space. There is now a sample space of 21 instead of 22.

13/21 = 0.619047619

0.619047619*100 = 61.9 ... % = 62% (rounded)

There is a chance of 62% of the second chosen being a girl.