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3 September, 13:37

How do I reflect over x=3?

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  1. 3 September, 13:55
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    This last claim is because x can be thought of as 2+a, where "a" could be negative! Now x needs to go to 2-a, but solveing for "a" in x=2+a gives a=x-2, so the new x is

    2-a = 2 - (x-2) = 4-x.

    (-1,1) = > (5,1)

    (0,4) = > (4,4)

    (-3,4) = > (7,4)
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