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Malia Gillespie
Mathematics
3 September, 13:37
How do I reflect over x=3?
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Ariana Proctor
3 September, 13:55
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This last claim is because x can be thought of as 2+a, where "a" could be negative! Now x needs to go to 2-a, but solveing for "a" in x=2+a gives a=x-2, so the new x is
2-a = 2 - (x-2) = 4-x.
(-1,1) = > (5,1)
(0,4) = > (4,4)
(-3,4) = > (7,4)
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