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25 October, 07:06

assume that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. the growth in the scale of motorcycles is 16% every year and that of cars is 25% every year. Find when the sale of cars will be more then the sale of motorcycles. shw your work

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  1. 25 October, 07:08
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    Final answer is approx 6.644 years.

    Step-by-step explanation:

    Given that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles is 16% every year and that of cars is 25% every year.

    So we can use growth formula:

    A = P (1 + r) ^t

    Then we get equation for motorcycles and cars as:

    A = 5.75 (1 + 0.16) ^t

    A = 3.5 (1 + 0.25) ^t

    Now we need to find about when the sale of cars will be more than the sale of motorcycles. So we get:

    3.5 (1 + 0.25) ^t > 5.75 (1 + 0.16) ^t

    3.5 (1.25) ^t > 5.75 (1.16) ^t

    3.5 (1.25) t. 5.75 (1.16) ^t

    (1.25) ^t / (1.16) > 5.75/3.5

    (1.25/1.16) ^t > 1.64287514286

    t·In (1.25/1.16) > In (1.64287514286)

    t > In (1.64285714286) / In (1.25/1.16)

    t > 6.6436473051

    Hence final answer is approx 6.644 years.
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