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16 June, 19:07

Find tan θ if sec θ = (sqrt26) / 5 and sin θ < 0.

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  1. 16 June, 19:23
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    So cos θ = 5/sqrt (26)

    adjacent = 5

    hypotenuse = sqrt 26

    by pythagoras opposite = 1

    so sin θ = 1/sqrt (26)

    and tan θ = 1/5
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